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xavaoneillx
Yeah it’s either A or B but the check part I am not use about. Try to check my work to see if it’s extraneous or not, then you’ll find the answer!
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gmany
[tex]\sqrt{x+9}-4=1\\\\The\ domain:\\x+9\geq0\to x\geq-9\\D:x\geq-9\\\\\sqrt{x+9}-4=1\ \ \ |+4\\\\\sqrt{x+9}=5\ \ \ |square\ both\ sides\\\\(\sqrt{x+9})^2=5^2\\\\|x+9|=25\to x+9=25\ \vee\ x+9=-25\ \ \ |-9\\\\x=16\in D\ \vee\ x=-36\notin D\\\\Answer:\ x=16[/tex]