Mash16363 Mash16363

04-07-2018
Mathematics

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Three consecutive multiples of 3 have a sum of 72. What is the least of these numbers?

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amayacbeau amayacbeau

04-07-2018

The least of these numbers is 21.

Since the numbers are consecutive, let 3x, 3x + 3, and 3x + 6 represent these numbers. Add these values, combine like terms, and solve for x.

3x + (3x + 3) + (3x + 6) = 72
9x = 63
x = 7

The smallest number is 3(7) = 21

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