Answer:
two solutions
x1=-8 , x2=2
Step-by-step explanation:
x^{2}+6x-16=0 move constant to the right
x^{2}=6x=16 add ([tex]\frac{6}{2} ^{2}[/tex]) to both sides of question
x^{2}+6x+([tex]\frac{6}{2} ^{2}[/tex])=16+([tex]\frac{6}{2} ^{2}[/tex])
x^{2}=6x+([tex]\frac{6}{2} ^{2}[/tex])=16+([tex]\frac{6}{2} ^{2}[/tex])
using a^{2}+2ab+b^{2}=(a+b)^{2}, factor the expression
[tex](x+\frac{6}{2} ^{2}=16+(\frac{6}{2})^{2}[/tex]
[tex](x+\frac{6}{2} ^{2}=25
reduce the fraction with 2
(x+3)^{2}=25
solve for x
the get final solution of x= -8 and x= 2
