test4261 test4261

03-02-2020
Chemistry

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How many atoms are present in 20.9 g of titanium

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gbustamantegarcia054 gbustamantegarcia054

04-02-2020

Answer:

atoms Ti = 2.193 E23 atoms

Explanation:

1 mol ≡ 6.022 E23 atoms
mm Ti = 47.867 g/mol

⇒ atoms Ti = (20.9 g Ti)×(mol/47.867 g)×(6.022 E23 atoms/mol)

⇒ atoms Ti = 2.193 E23 atoms

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