dogsaver14
dogsaver14
01-07-2016
Mathematics
contestada
What is the inverse of y = 2x^2 – 8?
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nobillionaireNobley
nobillionaireNobley
02-07-2016
[tex]y = 2x^2 - 8 \\ 2x^2 = y + 8 \\ x^2 = \frac{y+8}{2} \\ x = \sqrt{\frac{y+8}{2}} \\ f^{-1} (x)=\sqrt{\frac{x+8}{2}}[/tex]
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solve by substitution y=x+3 y=2x+5
