Answer:
36.75 grams of sulfuric acid will be required.
Explanation:
Moles of sodium hydroxide = 0.75 mol
[tex]2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O[/tex]
According to reaction, 2 moles of sodium hydroxide reacts with 1 mole of sulfuric acid ,then 0.75 moles of NaOH will :
[tex]\frac{1}{2}\times 0.75 mol=0.375 mol[/tex] sulfuric acid
Mass of 0.375 moles of sulfuric acid:
0.375 mol × 98 g/mol = 36.75 g
36.75 grams of sulfuric acid will be required.
