seng8320 seng8320
  • 02-05-2020
  • Mathematics
contestada

What are the vertical asymptote(s) and hole(s) for the graph of y= x-1 over X squared + 6x+ 8

Respuesta :

slinl slinl
  • 02-05-2020

Answer:

You have vertical asymptotes on x=-4,-2

Step-by-step explanation:

This question is very simple. Since you have a denominator all you need to do is factor the bottom and find the zeros. When you factor the bottom of the equation you should get (x+4)(x+2). Now you have to set the bottom equal to zero to find the zeros. This means (x+4)=0 and (x+2)=0 So you get two answers x=-4 and x=-2 Therefore your two vertical asymptotes are on x-4,-2

Answer Link

Otras preguntas

How many times can 20 go into 16
What is the quotient?
What is the surface area of the composite figure
Use two words from the sentence to form a compound word: The rain was so heavy during the storm, some streets were flooded.​
When writing a business letter, which of the following should be inclulded first?
find missing term.x/x2-4x+4-x/x2-3x+2= ?/(x-2)2(x-1)
By providing prospective terrorist with electronic chat rooms for interfacing online with others who share their attitudes, the Internet most likely serves as a
what is the common difference for the arithmetic sequence? -6, -1, 4, 9, 14​
what is the IQR of 62, 65, 93, 51, 55, 76, 79, 85, 55, 72, 78, 83, 91, and 82
what is the meaning of life? plz i need to know