Answer:
[tex]\frac{3x+11}{(x+3)(x+4)(x+5)}[/tex]
Step-by-step explanation:
Before adding we require the fractions to have a common denominator.
Multiplying the numerator/ denominator of the first fraction by (x + 5)
Multiplying the numerator/ denominator of the second fraction by (x + 3)
= [tex]\frac{x+5}{(x+3)(x+4)(x+5)}[/tex] + [tex]\frac{2(x+3)}{(x+3)(x+4)(x+5)}[/tex]
Now add the numerators leaving the common denominator
= [tex]\frac{x+5+2x+6}{(x+3)(x+4)(x+5)}[/tex]
= [tex]\frac{3x+11}{(x+3)(x+4)(x+5)}[/tex]
