Answer:
g(x) = [tex]9(\frac{1}{3})^x[/tex]
Step-by-step explanation:
Exponential function 'g' that can be written as g(x) = a.bˣ
From the graph attached,
Graph of the function passes through two points (0, 9) and (1, 3)
g(0) = a.b⁰
9 = a
Similarly, g(1) = a.b¹
3 = a.b
3 = 9(b)
b = [tex]\frac{3}{9}=\frac{1}{3}[/tex]
Therefore function will be,
g(x) = [tex]9(\frac{1}{3})^x[/tex]
