Answer:
1. 10 g / 100 g H₂O
2. 2 g / 100 g H₂O
Explanation:
Both questions ask about the solubility of cerium sulfate (Ce₂(SO₄)₃), meaning we need to focus on the dark blue line.
- 1. When X = 10 °C, the value in the Y axis is 10. So the solubility of cerium sulfate at 10 °C is 10 g/100 g H₂O.
- 2. Simmilarly, when x = 50 °C, Y is equal to 2 g / 100 g H₂O
