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03-03-2022
Mathematics

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for p(x) = 5x^3-2x^2+3x-6.is x=-1 is a root of p(x)?is x=1 is a root of p(x)

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03-03-2022

Answer:

just x = 1 is a root.

Step-by-step explanation:

p(-1) = 5(-1)³ - 2(-1)² + 3(-1) - 6 = -5 - 2 - 3 - 6 = -26

so x= -1 isn't root for p(x)

p(1) = 5(1)³ - 2(1)² + 3(1) - 6= 5 - 2 + 3 - 6= 0

so x = 1 is a root for p(x)

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