Respuesta :

Answer:

yes

Step-by-step explanation:

using the rule of exponents

[tex]\frac{a^{m} }{a^{n} }[/tex] = [tex]\frac{1}{a^{(n-m)} }[/tex] , then

[tex]\frac{9^2}{9^{7} }[/tex] = [tex]\frac{1}{9^{(7-2)} }[/tex] = [tex]\frac{1}{9^{5} }[/tex]