LaquanV93349 LaquanV93349
  • 03-11-2022
  • Mathematics
contestada

how would I simplify 3x^3-12x÷3x^3+6x^2-24x?

Respuesta :

IzamarP550509 IzamarP550509
  • 03-11-2022

To simplify:

[tex]3x^3-12x\div3x^3+6x^2-24x[/tex]

On division we get,

[tex]\begin{gathered} \frac{3x^3-12x}{3x^3+6x^2-24x}=\frac{3x(x^2-4)}{3x(x^2+2x-8)} \\ =\frac{(x^2-4)}{(x^2+2x-8)} \\ =\frac{(x+2)(x-2)}{(x-2)(x+4)_{}} \\ =\frac{x+2}{x+4} \end{gathered}[/tex]

Hence, the simplest form is,

[tex]\frac{x+2}{x+4}[/tex]

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