Respuesta :
					                   first integer: x
second integer: x+1
third integer: x+2
Set up an equation: 3x+3=243
3x=240
x=80
The integers are 80,81,82
					                
					             second integer: x+1
third integer: x+2
Set up an equation: 3x+3=243
3x=240
x=80
The integers are 80,81,82
					                   Three consecutive integers are n, n+1, and n+2 so
n+n+1+n+2=243
3n+3=243
3n=240
n=80
So the integers are 80,81, and 82
					                
					             n+n+1+n+2=243
3n+3=243
3n=240
n=80
So the integers are 80,81, and 82
 
			                   
					                  