williamxm01 williamxm01

02-07-2017
Chemistry

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How many moles of AgNO3 are present in 1.50 L of a 0.050 M solution?

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mimilaith mimilaith

02-07-2017

0.075 moles of AgNO3 is the answer ....

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CarlsenP CarlsenP

02-07-2017

c = n / V

n = c × V
n = 0,05 × 1,5 = 0,075[mol]

:-) ;-)

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