A ball is thrown straight up into the air, with an initial speed of 18.2 m/. How far has it gone after 1.00 s?

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01-10-2017
Physics

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A ball is thrown straight up into the air, with an initial speed of 18.2 m/. How far has it gone after 1.00 s?

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Yna9141 Yna9141 · Answer 1 · 2017-10-14T10:15:15+02:00

Yna9141 Yna9141

14-10-2017

The distance that the ball was able to travel at a given time is calculated through the equation,

d = Vot + (1/2)(g)(t²)

Then, we substitute the known values from the given above,

d = (-18.2 m/s)(1 s) + 0.5(-9.8 m/s²)(1 s)²
d= -23.1 m

Thus, the distance traveled by the ball after an hour is equal to 23.1 m

ANSWER: 23.1 m

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thisisfake1357924680 thisisfake1357924680 · Answer 2 · 2021-02-01T20:21:50+01:00

thisisfake1357924680 thisisfake1357924680

01-02-2021

Answer: 13.3 m

I got it right on Acellus

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