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A light beam in air strikes the surface of water at an angle of 35° to the normal. When it enters the water it bends toward the normal, making an angle of 25.5° to it. The velocity of light in air is approximately 300,000 km/s. What is the approximate velocity of light in water? A. 77,000 km/s B. 225,000 km/s C. 278,000 km/s D. 341,000 km/s

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jcherry99
Quick Answer B
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Sin(A)/Sin(B) = v1/v2
A = 25.5
B = 35
v2 = 300,000 km/hr
v1 = ???
Note that this is an inverse relationship.
Sin(25.5)/Sin(35) = v1/300000
v1 = [sin(25.5)/sin(35)] * 300000
sin(A) = 0.4305
Sin(B) = 0.5736
v1 = (0.4305)/0.5736 * 300000
v1 = 225000

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