Balance chemical equation for this reaction is,
C₃H₈ + 10 O₂ → 3 CO₂ + 4H₂O
According to this equation 44 g of C₃H₈ reacts with 320 g of O₂ to completely consume.
Now let's calculate amount of O₂ required to completely consume 13.4 g of C₃H₈,
44 g C₂H₈ was completely consumed by reacting = 320 g of O₂
13.4 g of C₂H₈ will require = X g of O₂
Solving for X,
X = (13.4 g × 320 g) ÷ 44 g
X = 97.45 g of O₂ is required to consume 13.4 g of C₂H₈
Now,
Let's calculate amount of C₂H₈ required to consume 4.35 g of O₂,
320 g of O₂ was consumed by reacting = 44 g of C₂H₈
4.35 g of O₂ will require = X g of C₂H₈
Solving for X,
X = (4.35 g ×44 g) ÷ 320
X = 0.598 g of C₂H₈ is required to consume 4.35 g of O₂
Result:
As the given amount of C₂H₈ requires 97.45 g of O₂, but we are provided only with 4.35 g, it means the oxygen will consume first.
So, Oxygen is the limiting reagent.
