Respuesta :
					                   To solve for A, we just have to isolate A on one side of the equation, like this:
[tex]BA+C=D \\ (BA+C)-C=(D)-C \\ BA=D-C \\ (BA)/B=(D-C)/B \\ A= \frac{D-C}{B} [/tex]
The answer is A=(D-C)/B.
Hope this helps!
					                
					             [tex]BA+C=D \\ (BA+C)-C=(D)-C \\ BA=D-C \\ (BA)/B=(D-C)/B \\ A= \frac{D-C}{B} [/tex]
The answer is A=(D-C)/B.
Hope this helps!
					                   BA + C = D
Subtract C on both sides
BA + C - C = D - C
BA = D - C
Divide B on both sides
[tex] \frac{BA}{B} =\frac{D-C}{B}\\\\\ \boxed{\bf{A =\frac{D-C}{B}}}[/tex]
					                
					                
					             Subtract C on both sides
BA + C - C = D - C
BA = D - C
Divide B on both sides
[tex] \frac{BA}{B} =\frac{D-C}{B}\\\\\ \boxed{\bf{A =\frac{D-C}{B}}}[/tex]
 
					                  