Respuesta :
					                   Let n = the first number. n + 1 = the second and n + 2 = the third number. So....
n + (n + 1) + (n + 2) = 159
3n + 3 = 159
3n = 156
n = 52
n + 1 = 53
n + 2 = 54
So the numbers are 52, 53, and 54.
					                
					             n + (n + 1) + (n + 2) = 159
3n + 3 = 159
3n = 156
n = 52
n + 1 = 53
n + 2 = 54
So the numbers are 52, 53, and 54.
					                   The middle one is their average, 159/3 = 53.
The numbers are 52, 53, 54.
					                
					             The numbers are 52, 53, 54.
 
			                   
					                  